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KBzml

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2Â¥2016-06-28 23:01:29
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KBzml

Ìú³æ (СÓÐÃûÆø)

ÒýÓûØÌû:
2Â¥: Originally posted by brucefan at 2016-06-28 23:01:29
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3Â¥2016-06-29 20:32:21
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brucefan

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3Â¥: Originally posted by KBzml at 2016-06-29 20:32:21
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4Â¥2016-06-30 01:13:35
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Ìú³æ (СÓÐÃûÆø)

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4Â¥: Originally posted by brucefan at 2016-06-30 01:13:35
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5Â¥2016-06-30 17:32:54
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brucefan

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5Â¥: Originally posted by KBzml at 2016-06-30 17:32:54
ÆäʵĿǰÏë´¦ÀíµÄÎÊÌâÇó½âsingle asperity½Ó´¥µ½´ïƽºâλÖõĽӴ¥µç×裬ĿǰÏÖÓеÄÀíÂÛ»ù±¾ÊÇÈ·¶¨single asperityµÄ´óС£¬´øÈë½Ó´¥µç×è¼ÆË㹫ʽ½øÐеç×è¹ÀË㣬֮ǰ½Ó´¥¹ýlammps,Ïë×ÅÊÇ·ñ¿ÉÒÔͨ¹ý΢¹Û³ß¶È϶ÔÓÚÉÏÊö ...

Usually, µçµ¼ÂÊ(electrical conductivity) refers to the intrinsic transport properties of a material. For a sample longer than the electron mean free path, conductivity sigma is related to conductance G by G=A*sigma/L, where A is the cross-sectional area (perpendicular to the transport direction) and L is the sample length. The inverse of the conductance G is the resistance R. But this resistance R is different from ½Ó´¥µç×è (contact resistance) R_c, which is a property of the interface (contact).  For the whole system, the total resistance R_tot can be considered as the sum of these two components: R_tot = R + R_c.

Anyway, I guess what you  are interested is to calculate the ½Ó´¥µç×è R_c. I think molecular simulation itself cannot give you the final answer. What molecular simulation might provide is the atomic configuration around the contact, which might be needed in a model which can calculate the ½Ó´¥µç×è.
6Â¥2016-06-30 19:19:38
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KBzml

Ìú³æ (СÓÐÃûÆø)

ÒýÓûØÌû:
6Â¥: Originally posted by brucefan at 2016-06-30 19:19:38
Usually, µçµ¼ÂÊ(electrical conductivity) refers to the intrinsic transport properties of a material. For a sample longer than the electron mean free path, conductivity sigma is related to conductanc ...

First of all, thank you very much for your detailed explaination of the contact resistance and electrical conductivity. And what you refer puzzle me a long time because I want to combime the  contact resistance(macro behacior) with micromechanism of  the  electrical conductivity. I believe that you said in the last is a correct advice for me now.
7Â¥2016-07-01 09:49:59
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