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邪美公子88

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[求助] 审稿意见---- 有关 spin state 的问题

我收到编辑给的审稿意见,其中一条是:
  The oxygen molecule is in triplet state. Is it accurate to use its energy in the expression of the energy of formation of surface vacancies? Is there a risk for inaccurate spin state in the expression? Did the authors use the energy of the triplet oxygen or the energy of the activate singlet oxygen?

   我做的是 CeO2, 我计算的O2 vasp INCAR 是:
SYSTEM = O2
ALGO = Fast
ENCUT = 400
ISTART = 0 ;
IBRION = 2
ICHARG = 2
ISIF = 2
EDIFF = 1E-5; EDIFFG = -0.001
ISMEAR = 0
ISPIN = 2 ; MAGMOM = 2*0.6
LORBIT = 11
LREAL = .False.
LWAVE = .False.
NELM = 200
NSW = 60
SIGMA = 0.1
GGA = PE

计算结果是:
  13 F= -.98588692E+01 E0= -.98588692E+01  d E =-.127335E+01  mag=     2.0000
curvature:  -0.06 expect dE=-0.741E-08 dE for cont linesearch -0.401E-08
ZBRENT: bisectioning
opt :   0.3226  next Energy=    -9.858869 (dE=-0.127E+01)
bond charge predicted
       N       E                     dE             d eps       ncg     rms          rms(c)
DAV:   1    -0.985886960696E+01   -0.11236E-05   -0.88896E-08    56   0.232E-03    0.115E-04
RMM:   2    -0.985886999766E+01   -0.39070E-06    0.00000E+00    20   0.451E-04
  14 F= -.98588700E+01 E0= -.98588700E+01  d E =-.127335E+01  mag=     2.0000
curvature:  -0.04 expect dE=-0.346E-08 dE for cont linesearch -0.971E-09
trial: gam= 0.00000 g(F)=  0.804E-07 g(S)=  0.000E+00 ort =-0.368E-03 (trialstep = 0.865E+00)
search vector abs. value=  0.805E-07
reached required accuracy - stopping structural energy minimisation


请问下,(1)我加的ISPIN=2 是计算的三线氧?
我去掉ISPIN以后,计算的结果比上面的能量大1eV左右,而这个加上ISPIN的能量是最低的,且有磁性,我个人认为是最低能量状态。
            (2)我整个计算是 spin-polarized,但是编辑问我有没有考虑 spin state ?  这个我如何回答?我自己找了些文献再看,但是还是不清楚这个问题如何回答.
   
              麻烦大家了!!!!!!!!!!
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