[交流] 积分求教

2楼: Originally posted by zyh700600 at 2019-10-09 11:29:24
令r'=x、cosψ=b，用Mathematica计算可得：





   \frac{1}{2} \left(\left(3 b^2-1\right) r^2 \log \left(\sqrt{-2 b r x+r^2+x^2}-b r+x\right)+(3 b r+x) \sqrt{-2 b r x+r^2+x^2}\right)  ...