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Edstrayer

版主 (著名写手)

方寸斗室小天地正气迷漫大世界

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10楼: Originally posted by peterflyer at 2015-09-02 13:46:42
大神好像把第一题的分母少了个x的平方,否则就成了(x-1)^x当x趋于无穷大时的极限了。...

不好意思哈,确实漏了平方,否则题目意思就变了
青葱岁月圣诞夜,浪漫歌舞迎新年。
11楼2015-09-02 16:57:19
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dragonship

铁杆木虫 (正式写手)

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5楼: Originally posted by peterflyer at 2015-09-01 15:33:52
已知 Lim{{sqrt-1}/ , x-->0}=2,
设极限的值为I,则原极限I中运用一次罗彼塔法则后得到:
I=Lim{{1/sqrt*}/ , x-->0}
=Lim{1*/3, x-->0}=2
故:Lim{f(x), x-->0}=6...

f'(x)*sinx的极限等于0是怎么出来的?如果f(x)=lnx, f'(x)=1/x  ,sinx/x的极限可是1

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12楼2015-09-03 06:35:17
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