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feixiaolin
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2Â¥2015-03-24 18:04:26
zaq123321
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Seems okay. Usually when i=j, the integral of the square of some base is constant. But here is infinity. Think in physical viewpoint, it makes some sense if we think 0x\infty = 0 since there is no \infty. Anyway, it's not very well-defined but makes some sense. |

3Â¥2015-03-24 19:55:07
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4Â¥2015-03-25 11:51:03














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