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ÒýÓûØÌû:
4Â¥: Originally posted by zaq123321 at 2015-03-24 19:48:30
Sorry about this. Then should we compute the second derivative, which is negative in (0,1)?
But the calculation looks pretty complex....

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for you, a thousand times over
5Â¥2015-03-24 20:38:37
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ÂäÒ¶ÎÞÉù===: ½ð±Ò+10, ¡ïÓаïÖú, ·Ç³£Ð»Ð»ÄãÄܹØ×¢Õâ¸öÎÊÌ⣡ 2015-03-26 01:42:30
Replace the second x^(2n) with x^n. Combine the second term and third term. Then each term is positive.
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2Â¥2015-03-24 15:56:57
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ÒýÓûØÌû:
2Â¥: Originally posted by zaq123321 at 2015-03-24 15:56:57
Replace the second x^(2n) with x^n. Combine the second term and third term. Then each term is positive.

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for you, a thousand times over
3Â¥2015-03-24 18:00:34
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zaq123321

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ÒýÓûØÌû:
3Â¥: Originally posted by ÂäÒ¶ÎÞÉù=== at 2015-03-24 18:00:34
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Sorry about this. Then should we compute the second derivative, which is negative in (0,1)?
But the calculation looks pretty complex.
Сľ³æ¸øÎÒÎÂů£¬¸øÎÒÏ£Íû£¬°®¾ÍÒª°®Ð¡Ä¾³æ¡£
4Â¥2015-03-24 19:48:30
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