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hqusurui

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10Â¥: Originally posted by feixiaolin at 2014-12-04 20:56:17
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11Â¥2014-12-04 20:59:35
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zaq123321

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hqusurui(feixiaolin´ú·¢): ½ð±Ò+4 2014-12-19 17:37:25
I think the general idea should work. You said you have figured out the reason why it conflicts with what you expected. You may first post here for others' reference.  I have several confusions. First what's the range [10-0.5, 10+0.5]? Is it used for reference? If you can guarantee that all the data is in this range, then I think you may need to remove the outliers first. After that, use normal distribution to represent this case as you did before. It should make sense.
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12Â¥2014-12-05 10:35:23
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hqusurui

Òø³æ (СÓÐÃûÆø)

ÒýÓûØÌû:
12Â¥: Originally posted by zaq123321 at 2014-12-05 10:35:23
I think the general idea should work. You said you have figured out the reason why it conflicts with what you expected. You may first post here for others' reference.  I have several confusions. Firs ...

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13Â¥2014-12-05 10:56:30
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hqusurui

Òø³æ (СÓÐÃûÆø)

ÒýÓûØÌû:
12Â¥: Originally posted by zaq123321 at 2014-12-05 10:35:23
I think the general idea should work. You said you have figured out the reason why it conflicts with what you expected. You may first post here for others' reference.  I have several confusions. Firs ...

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14Â¥2014-12-05 11:05:07
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zaq123321

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13Â¥: Originally posted by hqusurui at 2014-12-05 10:56:30
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If I understand correctly, in these 8 data. Two bigger, two smaller, 4 in middle. Just use one normal distribution is not good. Three normal distributions should be better. One group has 200 data, another group has 200 data and another group has 400 data. Then construct three creteria to handle this case. One normal distribution doesn't make sense. I don't need your data.
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15Â¥2014-12-05 11:20:17
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hqusurui

Òø³æ (СÓÐÃûÆø)

ÒýÓûØÌû:
15Â¥: Originally posted by zaq123321 at 2014-12-05 11:20:17
If I understand correctly, in these 8 data. Two bigger, two smaller, 4 in middle. Just use one normal distribution is not good. Three normal distributions should be better. One group has 200 data, a ...

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16Â¥2014-12-05 11:34:22
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zaq123321

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16Â¥: Originally posted by hqusurui at 2014-12-05 11:34:22
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One normal distribution is not enough since the data come from different sampling. Their ensambles are not the same. How can you just use one normal distribution to represent them?
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17Â¥2014-12-05 11:45:35
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hqusurui

Òø³æ (СÓÐÃûÆø)

ÒýÓûØÌû:
17Â¥: Originally posted by zaq123321 at 2014-12-05 11:45:35
One normal distribution is not enough since the data come from different sampling. Their ensambles are not the same. How can you just use one normal distribution to represent them?...

We have solved this problem by JMP. Thanks a lot.
18Â¥2014-12-07 12:38:13
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19Â¥2014-12-07 13:12:32
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