β-BBO确实是分type-I和type-II的,对于800nm,应该是用type-I的,我们的切割角度是19.8°。之前我曾经见过用OPA做倍频的实验,通过转β-BBO与激光的角度从而实现对不同频率的激光(1200nm,1500nm,1800nm)的相位匹配来进行倍频。
至于a-BBO,我猜测本质上和β-BBO是一样的,
“High temperature form BBO (α-BaB2O4) is an excellent negative uni-axial birefringent crystal. It has large birefringence coefficient and good transmission over a broad range, from 189nm to 3500nm. Unlike ß-BBO, α-BBO is not useful for NLO application due to the centric symmetry with its crystal structure.
α-BBO is excellent crystal in Glan Taylor, Glan Laser and Glan Thompson polarizer as well as walk-off beamsplitters, especially for high power and UV polarizers. This is due to their unique UV transparency, good mechanical properties and high damage threshold. Union Optic manufactures many Glan polarizers and beam displacers from high quality α-BBO crystals for UV and high power operations.”
通过Sellmeier方程可以计算出a-BBO是负色散的,其实和方解石效果是一样的~我也不知道哪种好,但是我们实验室里面一般都是用a-BBO来补偿石英什么的。
我计算800o光和400e光,在切割角度为19.8°的type-I型β-BBO,no800=1.6606,ne400=1.6605,是满足相位匹配的。但是利用refractiveindex(那个网站我也上过,谢谢师兄了~)上面的Sellmeier公式,你可以发现800的o光和400的e光折射率并不一样。而且只提供了BBO的该公式。而我在商家的介绍里面才找到对于a-BBO和β-BBO的折射率计算公式,虽然很接近但还是不一样。但我毕竟不是做BBO的,好多还是不是很清楚。