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feixiaolin
ÈÙÓþ°æÖ÷ (ÎÄ̳¾«Ó¢)
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ר¼Ò¾Ñé: +518 - Ó¦Öú: 942 (²©ºó)
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2014-08-23 12:11:09, 32 K
2Â¥2014-08-23 12:11:40
Edstrayer
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- É¢½ð: 4503
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- ×¢²á: 2014-03-25
- ¹ÜϽ: Êýѧ

3Â¥2014-08-23 12:42:04
peterflyer
ľ³æÖ®Íõ (ÎÄѧ̩¶·)
peterflyer
- ÊýѧEPI: 10
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- ½ð±Ò: 146172
- ºì»¨: 1374
- Ìû×Ó: 93091
- ÔÚÏß: 7694.3Сʱ
- ³æºÅ: 1482829
- ×¢²á: 2011-11-08
- ÐÔ±ð: GG
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¸Ðл²ÎÓ룬ӦÖúÖ¸Êý +1
airbaylor(feixiaolin´ú·¢): ½ð±Ò+1 2014-08-24 22:09:49
¸Ðл²ÎÓ룬ӦÖúÖ¸Êý +1
airbaylor(feixiaolin´ú·¢): ½ð±Ò+1 2014-08-24 22:09:49
| Õâ¸ö²»¶¨»ý·ÖÊǵò»µ½³õµÈ±»»ýº¯ÊýµÄ£¬Ò²¾ÍÊÇ˵Ëü²»¿É»ý¡£ÏêÇé¿É²Î¿¼ ·®Ó³´¨ ±àÖøµÄ ¸ßµÈÊýѧ½²Òå Éϲá pp372~374. |
4Â¥2014-08-23 18:21:34
³ÂÒåchenyi
½ð³æ (ÖøÃûдÊÖ)
- Ó¦Öú: 11 (СѧÉú)
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- רҵ: ·ºº¯·ÖÎö

5Â¥2014-08-23 18:27:17
elastic
½ð³æ (СÓÐÃûÆø)
- ÊýѧEPI: 1
- Ó¦Öú: 43 (СѧÉú)
- ½ð±Ò: 1426.4
- ºì»¨: 4
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airbaylor(feixiaolin´ú·¢): ½ð±Ò+5 2014-08-24 22:10:55
feixiaolin: ÊýѧEPI+1, elastic 2014-09-10 16:48:01
¸Ðл²ÎÓ룬ӦÖúÖ¸Êý +1
airbaylor(feixiaolin´ú·¢): ½ð±Ò+5 2014-08-24 22:10:55
feixiaolin: ÊýѧEPI+1, elastic 2014-09-10 16:48:01
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MATLABµÄ¼ÆËã½á¹û£º > syms x int('(x^3+1)^(-1/2)',x) ans = ((3^(1/2)*i + 3)*((x + (3^(1/2)*i)/2 - 1/2)/((3^(1/2)*i)/2 - 3/2))^(1/2)*((x + 1)/((3^(1/2)*i)/2 + 3/2))^(1/2)*((1/2 + (3^(1/2)*i)/2 - x)/((3^(1/2)*i)/2 + 3/2))^(1/2)*ellipticF(asin(((x + 1)/((3^(1/2)*i)/2 + 3/2))^(1/2)), -((3^(1/2)*i)/2 + 3/2)/((3^(1/2)*i)/2 - 3/2)))/(- (3^(1/2)*(i/2) - 1/2)*(3^(1/2)*(i/2) + 1/2) - x*((3^(1/2)*(i/2) - 1/2)*(3^(1/2)*(i/2) + 1/2) + 1) + x^3)^(1/2) >> a=int('(x^3+1)^(-1/2)',x) a = ((3^(1/2)*i + 3)*((x + (3^(1/2)*i)/2 - 1/2)/((3^(1/2)*i)/2 - 3/2))^(1/2)*((x + 1)/((3^(1/2)*i)/2 + 3/2))^(1/2)*((1/2 + (3^(1/2)*i)/2 - x)/((3^(1/2)*i)/2 + 3/2))^(1/2)*ellipticF(asin(((x + 1)/((3^(1/2)*i)/2 + 3/2))^(1/2)), -((3^(1/2)*i)/2 + 3/2)/((3^(1/2)*i)/2 - 3/2)))/(- (3^(1/2)*(i/2) - 1/2)*(3^(1/2)*(i/2) + 1/2) - x*((3^(1/2)*(i/2) - 1/2)*(3^(1/2)*(i/2) + 1/2) + 1) + x^3)^(1/2) >> pretty(a) 1/2 / x - 1/2 + #3 \1/2 / 1/2 - x + #3 \1/2 / 3/2 + #3 \ (3 + 3 i) | ------------ | #2 | ------------ | ellipticF| asin(#2), - -------- | \ #3 - 3/2 / \ 3/2 + #3 / \ #3 - 3/2 / ----------------------------------------------------------------------------------------- 3 1/2 (x + (- #1 - 1) x - #1) where #1 == (#3 - 1/2) (#3 + 1/2) / x + 1 \1/2 #2 == | -------- | \ 3/2 + #3 / 1/2 3 i #3 == ------ 2 |

6Â¥2014-08-23 22:11:17
chlsun60
ľ³æ (СÓÐÃûÆø)
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7Â¥2014-08-24 18:18:13
feixiaolin
ÈÙÓþ°æÖ÷ (ÎÄ̳¾«Ó¢)
-

ר¼Ò¾Ñé: +518 - Ó¦Öú: 942 (²©ºó)
- ¹ó±ö: 1.275
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- ¹ÜϽ: Êýѧ
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8Â¥2014-08-24 22:08:26













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