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[ Last edited by tshgth on 2013-12-20 at 21:15 ]
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2Â¥2013-12-20 22:14:14
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tshgth: ½ð±Ò+5 2013-12-20 23:36:20
1/x *log(1+ax)dx
=log(1+ax)d log(x)
=1/a *log(1+ax)d log(ax)
=1/a *log(1+ax)d log(1+ax)

=1/(2a)*(log(1+ax))^2
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3Â¥2013-12-20 22:27:50
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zjl20111015

ľ³æ (ÖøÃûдÊÖ)

ÒýÓûØÌû:
3Â¥: Originally posted by laohuajiang at 2013-12-20 22:27:50
1/x *log(1+ax)dx
=log(1+ax)d log(x)
=1/a *log(1+ax)d log(ax)
=1/a *log(1+ax)d log(1+ax)

=1/(2a)*(log(1+ax))^2

Ò»Ç󵼾Ͳ»¶Ô£¬Öм䲻ÊÇÄÇô»»ÔªµÄ£¬»¹ÓÐlogÒ»°ã±íʾÊÇ10Ϊµ×

[ ·¢×ÔСľ³æ¿Í»§¶Ë ]
Believe in yourself.
4Â¥2013-12-21 09:04:08
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zjl20111015

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Believe in yourself.
5Â¥2013-12-21 09:10:08
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laohuajiang

ÖÁ×ðľ³æ (Ö°Òµ×÷¼Ò)

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ÒýÓûØÌû:
4Â¥: Originally posted by zjl20111015 at 2013-12-21 09:04:08
Ò»Ç󵼾Ͳ»¶Ô£¬Öм䲻ÊÇÄÇô»»ÔªµÄ£¬»¹ÓÐlogÒ»°ã±íʾÊÇ10Ϊµ×
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6Â¥2013-12-21 09:18:45
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tshgth

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