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[ Last edited by sddtc888 on 2013-11-27 at 14:35 ]
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m0378: ½ð±Ò+1, лл²ÎÓë 2013-11-26 08:38:18
sddtc888: ±à¼­ÄÚÈÝ 2013-11-27 15:06
É£Ê÷Ö®Àá: ½ð±Ò+10, ¡ï¡ï¡ï¡ï¡ï×î¼Ñ´ð°¸ 2013-11-28 23:10:55
r=k2¡ÁCV3¡ÁCV5            (1)
(CV5CV2)/(CFe3CV4)=k1/k-1 ¡ú CV5=(k1CFe3CV4)/(k-1CFe2)´øÈ루1£©
r=(k2k1/k-1)(CV3CFe3CV4)/CFe2
-20.92=Ea1 - Ea-1
50.2=Ea2 + Ea1 - Ea-1
ËùÒÔEa2=71.12kJ/mol

[ Last edited by sddtc888 on 2013-11-27 at 15:06 ]
2Â¥2013-11-26 00:44:03
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r = k2[V5+][V3+]

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r(Õý) = r(Äæ)
¶ø r(Õý) = k1[Fe3+][V4+]£¬r(Äæ) = k-1[Fe2+][V5+]
ËùÒÔ k1[Fe3+][V4+] = k-1[Fe2+][V5+]
ËùÒÔ [V5+] = k1[Fe3+][V4+]/k-1[Fe2+]

Œ¢ÉÏʽ´úÈëµÚ¶þ²½·´Ó¦ËÙÂʹ«Ê½£¬ÏûÈ¥[V5+]£¬ËùÒÔ×Ü·´Ó¦ËÙÂÊΪ
r = (k1k2/k-1) • ([Fe3+][V3+][V4+]/[Fe2+])

µÚ¶þÎÊ
ÒòΪ±í¹ÛËÙÂʳ£ÊýΪ k1k2/k-1
ËùÒÔ±í¹Û»î»¯ÄÜ Ea = Ea(1) + Ea(2) - Ea(-1)
ÓÖÒòµÚÒ»²½·´Ó¦µÄ·´Ó¦ìÊ ¦¤H = Ea(1) - Ea(-1)
ËùÒÔ Ea = Ea(2) + ¦¤H
ËùÒÔ Ea(2) = Ea - ¦¤H = 50.2 - (-20.92) = 71.12 kJ/mol
I can safely said that nobody understands the quantum theory. ¡ª¡ª R. P. Feynman
3Â¥2013-11-27 15:01:09
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