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3Â¥: Originally posted by math2000 at 2013-10-07 16:51:35
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ÊÇÄı¾ÊéÉϵÄϰÌâ? Äã·¢¸öͼƬÉÏÀ´¿´¿´. ÎÒ¶ÔÕâ¸ö½áÂÛ´æÒÉ, ¶øÇÒÏëµ½ÁËÒ»¸ö¿ÉÄܵķ´Àý.
4Â¥2013-10-08 00:23:43
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math2000: ½ð±Ò+5, ¡ï¡ï¡ï¡ï¡ï×î¼Ñ´ð°¸, ·Ç³£¸Ðл£¬ËäÈ»ÎÒÒ²Ö¤Ã÷³öÀ´ÁË£¬µ«·½·¨±ÈÄãÌá³öµÄ·½·¨†ªà¶àÁË 2013-10-08 18:33:32
1.) When x=xyx, then x=x*yxy*x, by uniqueness,  y=yxy.
2.) Let a=xy, clearly a^2=a. Assume there is another b such that b^2=b, we want to show a=b.
[ Consider ab and c such that ab*c*ab=ab. Then ab* bc*ab=ab, so bc=c.
Similarly, ab* ca*ab=ab implies ca=c.
Now from c* ab*c=c, it gets c*b*c=c,  thus ab=b.  meanwhile, c*a*c=c, so ab=a too. Thus a=b. ]
3.) This a=b is the identity element for the group. We do not assume finiteness on the set G.
We_must_know. We_will_know.
5Â¥2013-10-08 03:58:33
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weft

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