| 查看: 1695 | 回复: 15 | |||
| 当前只显示满足指定条件的回帖，点击这里查看本话题的所有回帖 | |||
[求助]
关于POSCAR中晶矢的定义
|
|||
POSCAR里面的三到五行 的晶矢是怎么定义的 就想知道具体是怎么算出来的 哪位帮帮忙吧 1BX8)S@IP4H[EY2@E47[S@T.jpg |
回复此楼» 猜你喜欢
读博
已经有5人回复
-
到新单位后，换了新的研究方向，没有团队，持续积累2区以上论文，能申请到面上吗
已经有13人回复
-
博士申请都是内定的吗？
已经有6人回复
-
之前让一硕士生水了7个发明专利，现在这7个获批发明专利的维护费可从哪儿支出哈？
已经有5人回复
-
博士读完未来一定会好吗
已经有29人回复
-
投稿精细化工
已经有4人回复
-
高职单位投计算机相关的北核或SCI四区期刊推荐，求支招！
已经有4人回复
-
导师想让我从独立一作变成了共一第一
已经有9人回复
-
心脉受损
已经有5人回复
-
Springer期刊投稿求助
已经有4人回复
liqizuiyang
木虫 (著名写手)
- 应助: 59 (初中生)
- 金币: 6859.5
- 散金: 261
- 红花: 94
- 帖子: 2093
- 在线: 708.9小时
- 虫号: 2366686
- 注册: 2013-03-21
- 性别: GG
- 专业: 凝聚态物性 II ：电子结构
【答案】应助回帖
★ ★
感谢参与，应助指数 +1
franch: 金币+2, 谢谢回帖交流，， 2013-05-13 21:32:56
感谢参与，应助指数 +1
franch: 金币+2, 谢谢回帖交流，， 2013-05-13 21:32:56
|
楼主可以参考下PWscf的帮助文件，里面有14种布拉伐格子的原胞基矢的表达式。 ibrav structure celldm(2)-celldm(6) or: b,c,cosab,cosac,cosbc 0 free crystal axis provided in input: see card CELL_PARAMETERS 1 cubic P (sc) v1 = a(1,0,0), v2 = a(0,1,0), v3 = a(0,0,1) 2 cubic F (fcc) v1 = (a/2)(-1,0,1), v2 = (a/2)(0,1,1), v3 = (a/2)(-1,1,0) 3 cubic I (bcc) v1 = (a/2)(1,1,1), v2 = (a/2)(-1,1,1), v3 = (a/2)(-1,-1,1) 4 Hexagonal and Trigonal P celldm(3)=c/a v1 = a(1,0,0), v2 = a(-1/2,sqrt(3)/2,0), v3 = a(0,0,c/a) 5 Trigonal R, 3fold axis c celldm(4)=cos(alpha) The crystallographic vectors form a three-fold star around the z-axis, the primitive cell is a simple rhombohedron: v1 = a(tx,-ty,tz), v2 = a(0,2ty,tz), v3 = a(-tx,-ty,tz) where c=cos(alpha) is the cosine of the angle alpha between any pair of crystallographic vectors, tx, ty, tz are: tx=sqrt((1-c)/2), ty=sqrt((1-c)/6), tz=sqrt((1+2c)/3) -5 Trigonal R, 3fold axis <111> celldm(4)=cos(alpha) The crystallographic vectors form a three-fold star around <111>. Defining a' = a/sqrt(3) : v1 = a' (u,v,v), v2 = a' (v,u,v), v3 = a' (v,v,u) where u and v are defined as u = tz - 2*sqrt(2)*ty, v = tz + sqrt(2)*ty and tx, ty, tz as for case ibrav=5 6 Tetragonal P (st) celldm(3)=c/a v1 = a(1,0,0), v2 = a(0,1,0), v3 = a(0,0,c/a) 7 Tetragonal I (bct) celldm(3)=c/a v1=(a/2)(1,-1,c/a), v2=(a/2)(1,1,c/a), v3=(a/2)(-1,-1,c/a) 8 Orthorhombic P celldm(2)=b/a celldm(3)=c/a v1 = (a,0,0), v2 = (0,b,0), v3 = (0,0,c) 9 Orthorhombic base-centered(bco) celldm(2)=b/a celldm(3)=c/a v1 = (a/2, b/2,0), v2 = (-a/2,b/2,0), v3 = (0,0,c) -9 as 9, alternate description v1 = (a/2,-b/2,0), v2 = (a/2,-b/2,0), v3 = (0,0,c) 10 Orthorhombic face-centered celldm(2)=b/a celldm(3)=c/a v1 = (a/2,0,c/2), v2 = (a/2,b/2,0), v3 = (0,b/2,c/2) 11 Orthorhombic body-centered celldm(2)=b/a celldm(3)=c/a v1=(a/2,b/2,c/2), v2=(-a/2,b/2,c/2), v3=(-a/2,-b/2,c/2) 12 Monoclinic P, unique axis c celldm(2)=b/a celldm(3)=c/a, celldm(4)=cos(ab) v1=(a,0,0), v2=(b*cos(gamma),b*sin(gamma),0), v3 = (0,0,c) where gamma is the angle between axis a and b. -12 Monoclinic P, unique axis b celldm(2)=b/a celldm(3)=c/a, celldm(5)=cos(ac) v1 = (a,0,0), v2 = (0,b,0), v3 = (c*sin(beta),0,c*cos(beta)) where beta is the angle between axis a and c 13 Monoclinic base-centered celldm(2)=b/a celldm(3)=c/a, celldm(4)=cos(ab) v1 = ( a/2, 0, -c/2), v2 = (b*cos(gamma), b*sin(gamma), 0), v3 = ( a/2, 0, c/2), where gamma is the angle between axis a and b 14 Triclinic celldm(2)= b/a, celldm(3)= c/a, celldm(4)= cos(bc), celldm(5)= cos(ac), celldm(6)= cos(ab) v1 = (a, 0, 0), v2 = (b*cos(gamma), b*sin(gamma), 0) v3 = (c*cos(beta), c*(cos(alpha)-cos(beta)cos(gamma))/sin(gamma), c*sqrt( 1 + 2*cos(alpha)cos(beta)cos(gamma) - cos(alpha)^2-cos(beta)^2-cos(gamma)^2 )/sin(gamma) ) where alpha is the angle between axis b and c beta is the angle between axis a and c gamma is the angle between axis a and b |
9楼2013-05-11 10:23:37
2楼2013-05-10 11:22:22
3楼2013-05-10 13:11:16
4楼2013-05-10 14:57:57