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29Â¥: Originally posted by gemucai at 2013-04-27 09:04:46
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End of BFGS Geometry Optimization

     Final enthalpy =    -167.8961699933 Ry
Begin final coordinates
     new unit-cell volume =    409.58929 a.u.^3 (    60.69487 Ang^3 )

CELL_PARAMETERS (alat=  8.35030000)
   1.016078133   0.000000000   0.000000000
   0.000000000   1.016078133   0.000000000
   0.000000000   0.000000000   0.681378067

ATOMIC_POSITIONS (crystal)
Cr       0.000000000   0.000000000  -0.000000000
Cr       0.500000000   0.500000000   0.500000000
O        0.304047718   0.304047718  -0.000000000
O        0.695952282   0.695952282   0.000000000
O        0.804047718   0.195952282   0.500000000
O        0.195952282   0.804047718   0.500000000
End final coordinates



     A final scf calculation at the relaxed structure.
     The G-vectors are recalculated for the final unit cell
     Results may differ from those at the preceding step.

     Parallelization info
     --------------------
     sticks:   dense  smooth     PW     G-vecs:    dense   smooth      PW
     Min         858     858    234                35945    35945    5075
     Max         859     859    236                35946    35946    5076
     Sum        6869    6869   1877               287563   287563   40605



     bravais-lattice index     =            0
     lattice parameter (alat)  =       8.3503  a.u.
     unit-cell volume          =     409.5893 (a.u.)^3
     number of atoms/cell      =            6
     number of atomic types    =            2
     number of electrons       =        36.00
     number of Kohn-Sham states=           22
     kinetic-energy cutoff     =     300.0000  Ry
     charge density cutoff     =    1200.0000  Ry
     convergence threshold     =      3.8E-12
     mixing beta               =       0.7000
     number of iterations used =            8  plain     mixing
     Exchange-correlation      = SLA-PZ-NOGX-NOGC ( 1 1 0 0 0)
     EXX-fraction              =        0.00

     celldm(1)=   8.350300  celldm(2)=   0.000000  celldm(3)=   0.000000
     celldm(4)=   0.000000  celldm(5)=   0.000000  celldm(6)=   0.000000

     crystal axes: (cart. coord. in units of alat)
               a(1) = (   1.016078   0.000000   0.000000 )  
               a(2) = (   0.000000   1.016078   0.000000 )  
               a(3) = (   0.000000   0.000000   0.681378 )  

     reciprocal axes: (cart. coord. in units 2 pi/alat)
               b(1) = (  0.984176  0.000000  0.000000 )  
               b(2) = (  0.000000  0.984176  0.000000 )  
               b(3) = (  0.000000  0.000000  1.467614 )  


     PseudoPot. # 1 for Cr read from file:
     /home/liushichen/tools/codes/espresso-4.3.2/pseudo/Cr.pz-hgh.UPF
     MD5 check sum: 1ecfd84ed12b05c881064968d61b62c6
     Pseudo is Norm-conserving, Zval =  6.0
     Generated in analytical, separable form
     Using radial grid of 1183 points,  6 beta functions with:
                l(1) =   0
                l(2) =   0
                l(3) =   0
                l(4) =   1
                l(5) =   1
                l(6) =   2

     PseudoPot. # 2 for  O read from file:
     /home/liushichen/tools/codes/espresso-4.3.2/pseudo/O.pz-hgh.UPF
     MD5 check sum: 9c3213c38e11527cd347dae851a6ebc4
     Pseudo is Norm-conserving, Zval =  6.0
     Generated in analytical, separable form
     Using radial grid of 1095 points,  1 beta functions with:
                l(1) =   0

     atomic species   valence    mass     pseudopotential
        Cr             6.00    52.00000     Cr( 1.00)
        O              6.00    16.00000      O( 1.00)

     Starting magnetic structure
     atomic species   magnetization
        Cr           0.500
        O            0.000

     LDA+U calculation, Hubbard_lmax = 2
     atomic species  L   Hubbard U  Hubbard alpha
        Cr           2    0.220496    0.000000

     16 Sym.Ops. (with inversion)


   Cartesian axes

     site n.     atom                  positions (alat units)
         1           Cr  tau(   1) = (   0.0000000   0.0000000  -0.0000000  )
         2           Cr  tau(   2) = (   0.5080391   0.5080391   0.3406890  )
         3           O   tau(   3) = (   0.3089362   0.3089362  -0.0000000  )
         4           O   tau(   4) = (   0.7071419   0.7071419   0.0000000  )
         5           O   tau(   5) = (   0.8169753   0.1991028   0.3406890  )
         6           O   tau(   6) = (   0.1991028   0.8169753   0.3406890  )
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31Â¥2013-05-07 19:37:45
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31Â¥: Originally posted by ÁõÊ˳¿ at 2013-05-07 19:37:45
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33Â¥: Originally posted by ÁõÊ˳¿ at 2013-05-08 13:11:16
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