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  • ¸½¼þ 1 : jp207342z[1]_Cl_JPCC.pdf
  • 2012-09-22 16:46:28, 2.93 M

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cenwanglai

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cenwanglai: »ØÌûÖö¥ 2012-09-22 16:49:38
fzx2008: ½ð±Ò+3, лл·ÖÏí 2012-09-23 16:30:23
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1. Why the ENCUT = 409 eV is used? How dit you get the value 409?

ENCUT=409eV corresponds to the cutoff used for Cl in the "hard"
pseudopotential (Cl_h). If you looked for the keyword "ENMAX" into the
POTCAR file corresponding to the hard Cl pseudopotential, you'll get:

ENMAX  =  409.136

To avoid comparing calculations obtained using different basis sets
(e.i., different cutoff for the plane waves expension), we explicitly
set ENCUT=409 in all the calculations including those not involving Cl
(for instance the oxygen molecule in the gas phase).

> 2. The number of unpaired electrons (Ns) was considered. How can you
assign the  Ns and fix it during geo optimaztion? Could you please show
me the corresponding TAG in INCAR or other ways to make it?

The number of unpaired electrons is fixed by the keyword "NUPDOWN". For
instance "NUPDOWN=1" in the INCAR file means Ns=1 in the paper. The
value of "NUPDOWN" appears in the "OSZICAR" and "out" files after each
electronic minimization. Look at the number given after "mag" (for
instance "mag=     0.0000" means "NUPDOWN = 0". If you don't set the
value of "NUPDOWN" in the INCAR file, VASP will compute the
magnetization automatically. The problem with this approach is that the
total magnetic moment may vary from one step to another during the
geometry optimization. Personally, I prefer to fix NUPDOWN during the
calculation and try different value of NUPDOWN. This ensure that I get
the lowest "spin state" for a given geometry. Furthermore, this approach
ensure the fulfilment of the "spin conservation" (see S. Chretien and H.
Metiu J. Chem. Phys. 129(7), 074705 (2008)).
8Â¥2012-09-22 16:49:15
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fzx2008

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liliangfang: ½ð±Ò+2, лл½»Á÷ 2012-09-22 10:53:56
cenwanglai: ½ð±Ò+3, ¡ï¡ï¡ïºÜÓаïÖú, лл»Ø¸´¡£409ÊÇClµÄhardÊÆÀïÃæµÄENMAX. 2012-09-22 16:53:46
1.¡°409¡±£¬ºÜÓпÉÄÜÊÇØÍÊÆÖеÄENMAX»òÕßENMAXµÄ1.3±¶£¬Ò²ÓпÉÄÜÊÇ×÷Õß×Ô¼ºÌØÒâÉèÖõÄÕâô¸öÖµ¡£ÎÒ¾õµÃ¸ú400»òÕß450»ù±¾²î±ð²»´ó¡£

2.NsÊdzɵ¥µç×ÓÊýÄ¿£¬¹ØºõÊÇ·ñ×ÔÐý¼«»¯¡¢¸ßµÍ×ÔÐý̬µÈ¡£

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2Â¥2012-09-22 00:37:48
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ChemiAndy

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liliangfang: ½ð±Ò+2, лл½»Á÷ 2012-09-22 10:54:02
cenwanglai: ½ð±Ò+3, ¡ï¡ï¡ïºÜÓаïÖú, ¸Ðл»Ø¸´~ 2012-09-22 17:02:42
ÒòΪVASP½Ø¶Ï°ë¾¶ÉèÖõĵ¥Î»ÊÇRy
¶øËüÓõÄÊÇ15Ry, 1Ry=27.21eV, 15Ry=409eV

» ±¾ÌûÒÑ»ñµÃµÄºì»¨£¨×îÐÂ10¶ä£©

3Â¥2012-09-22 06:35:22
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fzx2008: ½ð±Ò+1, лл»ØÌû£¡ 2012-09-22 11:51:13
ÒýÓûØÌû:
3Â¥: Originally posted by ChemiAndy at 2012-09-22 06:35:22
ÒòΪVASP½Ø¶Ï°ë¾¶ÉèÖõĵ¥Î»ÊÇRy
¶øËüÓõÄÊÇ15Ry, 1Ry=27.21eV, 15Ry=409eV

²»¶Ô°É£¬1Ry=13.6ev¡£1a.u=27.21ev°É¡£
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