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moonbear

Ìú³æ (СÓÐÃûÆø)

[ÇóÖú] ½ô¼±ÇóÖúxi2004ÀÏʦ

xi2004ÀÏʦ,ÄúºÃ!±¾ÈËÐÂÊÖ,ͶActa-E,Éó¸åÈËÒâ¼ûÈçÏÂ:
You need to move two independent solvent molecules
into new positions, where they will show O7---H7C...O6 and O6---H6A...O3
hydrogen bonds WITHOUT any symmetry codes (i.e. ALL three  moieties
will be really positioned in one asymmetric part).
To do it, you have to transform the atomic coordinates of all atoms for each
solvent molecule using proper symmetry operation.
After such re-positioning, prepare new Fig. 1 without H-atoms except only two -
draw atoms H6A and H7C involved in hydrogen-bonding.
Show H...O hydrogen-bonding by dashed lines. Draw displacement
ellipsoids with 30% probability.
Use the following Legend:
"The content of asymmetric part of the tile compound showing the
atomic numbering and 30% probabilty displacement ellipsoids.
H atoms not inlvolved in hydrogen-bonding (dashed lines)
omitted for clarity."
µÚÒ»´Î×÷ͼÉó¸åÈ˲»ÂúÒâ,ͨ¹ýÓʼþÇë½ÌËû,¸ø³öÈçϽ¨Òé:
Use the following transformations:
1. For the the molecule with O6, C34 & C33 and attached H atoms,
change atomic coordinates from (x, y, z) to (x-1, y, z).
1. For the the molecule with O7, C36 & C35 and attached H atoms,
change atomic coordinates from (x, y, z) to (1-x, 2-y, 1-z).
ºóÇëÈË×÷ͼ(¼û¸½¼þ)
Éó¸åÈ˻ظ´:
The current Fig. 1 shows the whole unit cell (but NOT an asymmetric part).
Draw dsiplacement ellipsoids for all non-H atoms.
Ŀǰ¸å¼þ±»³·»Ø,ÔÙͶÓֻص½Ô­Éó¸åÈË.½ô¼±ÇóÖú,Íò·Ö¸Ðл!
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  • 2011-12-24 19:19:10, 9.77 K

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ÌìÇç8986

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5Â¥: Originally posted by ÌìÇç8986 at 2011-12-26 13:55:28:
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