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lov520

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ag_mirabel

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lov520(½ð±Ò+5, ·­ÒëEPI+1): 2010-06-05 15:03:36
wypward(½ð±Ò+1):»¶Ó­Ð³棬лл²ÎÓë 2010-06-07 09:33:57
The reason might be that the metal oxide of the catalyst is adsorption center as well as oxidation center. It adsorps O2 that accumulates on its surface to form oxygen species. Then, SO3 and CO are adsorped too. CO reacts with the active oxygen species to generate co2, while so3 changes into metal sulfate. With the reaction's undergoing,  the metal oxide gradually becomes metal sulfate and decreases. The reduced reaction degree of CO + 1/2O2 ¡ú CO2 leads to a decrease in co2's yield quantity. Meanwhile, as the reaction degree of CO +1/2O2¡úCO2 and SO2 +1/2O2¡úSO3 lessens, the amount of o2 increases. This agrees with the principles of the experimental data.

[ Last edited by ag_mirabel on 2010-6-5 at 11:53 ]
2Â¥2010-06-05 11:52:27
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benmao_mogu

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The weaker of the intensity of reaction CO + 1/2O2 ¡ú CO2, the smaller of the production of CO2.However, with the reactions CO +1/2O2¡úCO2 and SO2 +1/2O2¡úSO3 down,the amount of O2 increases continually.¹þ¹þ ʦÐÖ£¡£¡
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3Â¥2010-06-05 15:33:09
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lov520

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