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jingcong198203

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[交流] 【讨论】小肽含量测定 已有1人参与

欧洲药典6.0版3038页测定Leuprorelinum   C59H84N16O12含量的方法用的是高氯酸滴定, 序列5-Oxo-L-prolyl-L-histidyl-L-tryptophyl-L-seryl-L-tyrosyl-D-leucyl-L-leucyl-L-arginyl-N-ethyl-L-prolinamide.  具体内容:Dissolve 0.100 g in 3 ml of anhydrous formic acid R. Add 30 ml of anhydrous acetic acid R. Titrate with 0.1 M perchloric acid using 0.1 ml of naphtholbenzein solution R as indicator(萘酚苯基甲醇), until the colour changes from brownish-yellow to green.1 ml of 0.1 M perchloric acid is equivalent to 13.12 mg of C6H13NO2.
还有欧洲药典上4392页的测定Tetracosactidum也是电位滴定,具体内容:Dissolve 0.250 g in 50 ml of alcohol R and add 5.0 ml of 0.01 M hydrochloric acid. Carry out a potentiometric titration (2.2.20), using 0.1 M sodium hydroxide. Read the volume added between the 2 points of inflexion. 1 ml of 0.1 M sodium hydroxide is equivalent to 30.08 mg of C15H25ClN2O2.
我不清楚是什么原理?诸位虫友,可以给解释一下吗,非常感谢!
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jingcong198203

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测定Leuprorelinum 的方法为什么测定的是亮氨酸啊(C6H13NO2) ?
2楼2010-04-28 10:11:13
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jingcong198203

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不好意思,以下内容弄错了。还有欧洲药典上4392页的测定Tetracosactidum也是电位滴定,具体内容:Dissolve 0.250 g in 50 ml of alcohol R and add 5.0 ml of 0.01 M hydrochloric acid. Carry out a potentiometric titration (2.2.20), using 0.1 M sodium hydroxide. Read the volume added between the 2 points of inflexion. 1 ml of 0.1 M sodium hydroxide is equivalent to 30.08 mg of C15H25ClN2O2.
3楼2010-04-28 10:21:38
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