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我看co频率计算有一段这样写是什么意思啦?请教前辈
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Finite differences progress:
Degree of freedom: 2/ 2
Displacement: 2/ 2
Total: 4/ 4
FORCES
------
INITIAL FORCE
0.000000 0.000000 -0.066860
0.000000 0.000000 0.066860
DOF: 1 ATOM: 1 AXIS: 3 DISPLACEMENT: 1
0.000000 0.000000 -2.526029
0.000000 0.000000 2.526029
DOF: 1 ATOM: 1 AXIS: 3 DISPLACEMENT: 2
0.000000 0.000000 2.069092
0.000000 0.000000 -2.069092
DOF: 2 ATOM: 2 AXIS: 3 DISPLACEMENT: 1
0.000000 0.000000 2.062261
0.000000 0.000000 -2.062261
DOF: 2 ATOM: 2 AXIS: 3 DISPLACEMENT: 2
0.000000 0.000000 -2.511030
0.000000 0.000000 2.511030
DYNMAT
------
2 1 1 2
16.000 12.011
1 1 0.0000 0.0000 0.0200
0.000000 0.000000 -2.297561
0.000000 0.000000 2.297561
2 1 0.0000 0.0000 0.0200
0.000000 0.000000 2.286646
0.000000 0.000000 -2.286646
SECOND DERIVATIVES (NOT SYMMETRIZED)
------------------------------------
1Z 2Z
1Z -114.878038 114.878038
2Z 114.332280 -114.332280
SECOND DERIVATIVES (SYMMETRYZED)
--------------------------------
1Z 2Z
1Z -114.878038 114.605159
2Z 114.605159 -114.332280
MASS-WEIGHTED SECOND DERIVATIVES
--------------------------------
1Z 2Z
1Z -7.179877 8.267127
2Z 8.267127 -9.518964
Eigenvectors and eigenvalues of the dynamical matrix
----------------------------------------------------
1 f = 63.884308 THz 401.396943 2PiTHz 2130.951061 cm-1 264.204354 meV
X Y Z dx dy dz
0.000000 0.000000 0.000000 0 0 -0.655715
0.000000 0.000000 1.143000 0 0 0.755008
2 f/i= 0.075306 THz 0.473159 2PiTHz 2.511925 cm-1 0.311439 meV
X Y Z dx dy dz
0.000000 0.000000 0.000000 0 0 -0.755008
0.000000 0.000000 1.143000 0 0 -0.655715
Eigenvectors after division by SQRT(mass)
Eigenvectors and eigenvalues of the dynamical matrix
----------------------------------------------------
1 f = 63.884308 THz 401.396943 2PiTHz 2130.951061 cm-1 264.204354 meV
X Y Z dx dy dz
0.000000 0.000000 0.000000 0 0 -0.163929
0.000000 0.000000 1.143000 0 0 0.217852
2 f/i= 0.075306 THz 0.473159 2PiTHz 2.511925 cm-1 0.311439 meV
X Y
Z dx dy dz
0.000000 0.000000 0.000000 0 0 -0.188752
0.000000 0.000000 1.143000 0 0 -0.189202
Finite differences POTIM= 2.000000000000000E-002
LATTYP: Found a simple cubic cell.
ALAT = 8.0000000000
Lattice vectors:
A1 = ( 8.0000000000, 0.0000000000, 0.0000000000)
A2 = ( 0.0000000000, 8.0000000000, 0.0000000000)
A3 = ( 0.0000000000, 0.0000000000, 8.0000000000)
Subroutine PRICEL returns:
Original cell was already a primitive cell.
Analysis of symmetry for initial positions (statically):
Routine SETGRP: Setting up the symmetry group for a
simple cubic supercell. |
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