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inter_dudu

木虫 (著名写手)

[交流] 【求助】求助紫外光谱

小弟光谱分析没学好。。文献看不懂。。向各位大哥大姐求教这图啥意思。。
The absorption spectra of 1, CR1, [Eu(tta)3], and acidified
N-(Rhodamine-6G)lactamethylenediamine are shown in
Figure 2. Free CR1 displays an intensive absorption band in
the visible region centered at 415 nm that arises from the
coumarin chromophore (Supporting Information Figure S5.1)
and a weak band at about 302 nm, which is attributed to
absorption of the ring-closed tautomeric form of the Rhodamine
6G moiety (Supporting Information Figure S5.2). The
UV/Vis absorption spectrum of 1 displays three main
absorption bands centered at 345, 415, and 525 nm. By
comparison of the absorption spectra of [Eu(tta)3], CR1, and
1, the first two were mainly assigned to the characteristic
absorption maxima of the Eu-TTA moiety and the coumarin
chromophore, respectively. The last band, which is absent in
CR1, should be assigned to the absorption of the ring-opened
tautomer of the Rhodamine 6G chromophore,[14] that is, the
carbonyl group of the Rhodamine 6G moiety is coordinated
to the Eu center and the attached spiro ring has opened to
make green emission of 1 possible.
Thus, 1 exhibits characteristic blue emission of the
coumarin fluorophore centered at 460 nm, green Rhodamine
emission centered at 550 nm, and typical red emission of the
EuIII ion with dominant peak at 612 nm when its solution in
acetonitrile (50 mm) is excited at 415, 525, and 360 nm,
respectively (Figure 3). The quantum yields of the blue,
green, and red emissions are about 0.056, 0.085 and 0.005,
respectively.[15] While a few organic dyes have been reported
that exhibit tunable emissive properties,[8a] the generation of
pure blue, green, and red emissions in a single-component dye
by simply changing the excitation wavelengths is extremely
appealing and significant. Such color-tunable materials may
be promising candidates for emitting “pure” white light by
controllably tailoring blue, green, and red primary colors that
fully span the entire visible spectrum.
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zxz.1982

至尊木虫 (职业作家)

Charles911

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inter_dudu(金币+3,VIP+0): 8-25 17:16
引用回帖:
Originally posted by inter_dudu at 2009-8-25 16:55:
小弟光谱分析没学好。。文献看不懂。。向各位大哥大姐求教这图啥意思。。
The absorption spectra of 1, CR1, [Eu(tta)3], and acidified
N-(Rhodamine-6G)lactamethylenediamine are shown in
Figure 2. ...

就是图中四种化合物在横坐标所示的波长范围内的光谱图啊
有波峰--最大吸收值,波谷--最小吸收值
大段英文没看
有什么疑问吗?
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2楼2009-08-25 17:05:48
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inter_dudu

木虫 (著名写手)

看不懂啊。。这图能得到什么信息?
3楼2009-08-25 17:16:26
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yzh_0083

银虫 (初入文坛)


inter_dudu(金币+1,VIP+0): 8-26 13:42
给出了四种染料的紫外特征吸收,根据官能团的不同对应在不同的波长上有强吸收
4楼2009-08-25 17:55:32
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liujunhero

新虫 (文学泰斗)

文献杰出贡献文献杰出贡献


inter_dudu(金币+1,VIP+0): 8-26 13:43
关键是要根据最大吸收解释出对应的官能团即可
5楼2009-08-25 21:08:49
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heihei0404

银虫 (小有名气)

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inter_dudu(金币+15,VIP+0): 8-26 13:43
图2为这四种物质的吸收光谱,从图中可看出,CR1在415nm可见区内有较大吸收,在302nm处有弱吸收,其中415nm处的峰是由香豆素(coumarin chromophore)内电子跃迁产生,(由图 S5.1可知),302nm处的峰则来自闭环的若丹明异构体(the ring-closed tautomeric form of the Rhodamine6G moiety )产生,(由图S5.2可知)
1在345nm,415nm和525nm处均有吸收峰,比较[Eu(tta)3], CR1, 和1三种物质的吸收峰,[Eu(tta)3]和CR1分别在345nm,415nm有吸收。在525nm处CR1没有吸收峰,这是由于若丹明生色团开环造成的,也就是说,若丹明6G基团的羰基与Eu中心结合,形成螺环使1有可能发射绿光。(注:525nm处为绿光)因此,由1可看出发出蓝光的香豆素荧光中心位置在460nm,绿色若丹明发射中心在550 nm,而EuIII离子典型的红色发射主峰在612nm。而它溶解在乙腈中(50mm)则分别发出415,525和360nm的光(见图3),蓝色、绿色和红色的量子产率分别为0.056,0.085和0.005,有报导说个别有机染料具有可调发射特性,在单一组分染料中通过改变激发波长得到纯蓝色,绿色和红色光及具有吸引力和重要性,这种颜色可调材料可能成为发射白光的候选物质,因为能完全跨越整个可见光谱的蓝色,绿色和红色三种主要颜色能够形成白光。
6楼2009-08-26 12:17:51
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