38楼: Originally posted by Edstrayer at 2016-04-03 01:33:27
\frac{1}{1+x^6}=\frac{\frac{1}{3}}{1+x^2}+\frac{\frac{1}{2\sqrt{3}}x+\frac{1}{3}}{x^2+\sqrt{3}x+1}+\frac{-\frac{1}{2\sqrt{3}}x+\frac{1}{3}}{x^2-\sqrt{3}x+1}

3楼: Originally posted by i维数 at 2016-04-02 12:56:54
将1+x^6分解成3个形如x^2+ax+b的乘积，然后将1/(1+x^6)拆分成几个易积分的有理函数，或者考虑ln(1+x^6)的分部积分