[latex]x\cdot 2^{\frac{A}{x}} + y\cdot 2^{\frac{B}{y}} \geq (x+y)\cdot 2^{\frac{A+B}{x+y}}, x>0,y>0,A>0,B>0[/latex] 返回小木虫查看更多
可用 凸函数不等式 证此。 令: a/x = c b/y = d 有: a = c*x b = d*y (a+b)/(x+y) = (c*x+d*y)/(x+y) 要证的 不等式 变为: x*2^c + y*2^d >= (x+y)*2^((c*x+d*y)/(x+y)) 此即: (x/(x+y))*2^c + (y/(x+y))*2^d >= 2^( (x/(x+y))*c + (y/(x+y))*d ) 上式即为 凸函数不等式。,
可用 凸函数不等式 证此。
<img src="https://t1.picb.cc/uploads/2021/04/03/ZBk4S8.jpg" alt="ZBk4S8.jpg" border="0" />
https://t1.picb.cc/uploads/2021/04/03/ZBk4S8.jpg
<img src="https://t1.picb.cc/uploads/2021/ ... g">
可用 凸函数不等式 证此。
令:
a/x = c
b/y = d
有:
a = c*x
b = d*y
(a+b)/(x+y) = (c*x+d*y)/(x+y)
要证的 不等式 变为:
x*2^c + y*2^d >= (x+y)*2^((c*x+d*y)/(x+y))
此即:
(x/(x+y))*2^c + (y/(x+y))*2^d >= 2^( (x/(x+y))*c + (y/(x+y))*d )
上式即为
凸函数不等式。,
可用 凸函数不等式 证此。
<img src="https://t1.picb.cc/uploads/2021/04/03/ZBk4S8.jpg" alt="ZBk4S8.jpg" border="0" />
https://t1.picb.cc/uploads/2021/04/03/ZBk4S8.jpg
<img src="https://t1.picb.cc/uploads/2021/ ... g">